0、引言
在开发的过程中,很多业务场景需要一个树形结构的结果集进行前端展示,也可以理解为是一个无限父子结构,常见的有报表指标结构、菜单结构等。Java中递归实现树形结构的两种常见方式如下:
- Java7及以下纯Java递归实现
- Java8及以上借助lamda表达式实现
1、数据准备
Java实体类NodePO对应数据库表
package com.wbs.pojo; import lombok.Data; import lombok.NoArgsConstructor; import java.util.List; @Data @NoArgsConstructor public class NodePO { /** * 当前节点id */ private String id; /** * 当前节点名称 */ private String name; /** * 父级节点id */ private String parentId; /** * 当前节点序号 */ private String orderNo; /** * 子集节点 */ private List children; /** * 构造函数 * @param id * @param name * @param parentId * @param orderNo */ public NodePO(String id,String name,String parentId,String orderNo){ this.id = id; this.name = name; this.parentId = parentId; this.orderNo = orderNo; } }
自己造一些数据模拟从数据库中查询出来的数据:
static final List nodePOs = Arrays.asList( new NodePO("1","一级节点1",null,"_0001"), new NodePO("2","二级节点1.1","1","_0002"), new NodePO("3","二级节点1.2","1","_0003"), new NodePO("4","一级节点2",null,"_0004"), new NodePO("5","二级节点2.1","4","_0005"), new NodePO("6","二级节点2.2","4","_0006"), new NodePO("7","三级节点2.2.1","6","_0007"), new NodePO("8","一级节点3",null,"_0008"), new NodePO("9","二级节点3.1","8","_0009"), new NodePO("10","三级节点3.1.1","9","_0010"), new NodePO("11","四级节点3.1.1.1","10","_0011"), new NodePO("12","五级节点3.1.1.1.1","11","_0012") );
2、类型转化
从开发的过程中发现直接操作实体类集合,专门指定某一个实体类封装的方法是不具有普适性的,所以将实体类集合统一转化为Map集合,操作方便,具有一定的普适性:
List
BeanMapUtils自己简单封装一个工具类(不惧普适性勿喷):
package com.wbs.util; import com.alibaba.fastjson.JSON; import com.alibaba.fastjson.JSONObject; import com.google.common.collect.Lists; import com.google.common.collect.Maps; import lombok.SneakyThrows; import org.springframework.cglib.beans.BeanMap; import java.util.*; import java.util.function.Function; import java.util.stream.Collectors; /** * @author 一宿君 * @version Id: BeanMapUtils.java, v 0.1 Administrator Exp $$ * @date 2022-10-13 14:24:20 * @desc java实体类和map相互转换工具类 */ public class BeanMapUtils { /** * 将实体类对象属性转化为map对象 * @param t * @param * @return */ public static Map beanToMap(T t) { Map map = new HashMap(); if (t != null) { if (t instanceof JSONObject){ return (JSONObject)t; } BeanMap beanMap = BeanMap.create(t); for (Object key : beanMap.keySet()) { map.put(key.toString(), beanMap.get(key)); } } return map; } /** * 将map对象中转化为实体类对象 * @param map * @param clazz * @param * @return * @throws Exception */ public static T mapToBean(Map map,Class clazz) throws Exception { T bean = clazz.newInstance(); if (bean instanceof JSONObject){ JSONObject jsonObject = (JSONObject)bean; Set
其中org.springframework.cglib.beans.BeanMap;
是org.springframework:spring-core
依赖下的工具包,spring-core
核心依赖只要导入spring-boot-starter
依赖即可
org.springframework.bootspring-boot-starter2.2.0.RELEASE
3、递归实现方法
3.1、Java7及以下纯Java递归实现
既然是Java7及以下实现方式,那排序也用最原始的冒泡排序:
/** * 冒泡排序,小的在前,大的在后 * @param list * @return */ public static List> sortJava7Map(List > list){ if(CollectionUtils.isEmpty(list)){ return Lists.newArrayList(); } boolean flag; int size = list.size(); for (int i = 0; i frontMap = list.get(j - 1); Map afterMap = list.get(j); if (String.valueOf(frontMap.get("orderNo")).compareTo(String.valueOf(afterMap.get("orderNo"))) > 0){ list.set(j - 1,afterMap); list.set(j,frontMap); flag = true; } } //如果没有发生位置互换,则退出循环 if (!flag){ break; } } return list; }
给定一个节点,获取它的所有子节点:
/** * Java7及以下版本获取子节点的方式 * @param parentNode * @param allList * @return */ public static List> getJava7Children(Map parentNode,List > allList){ //存放当前节点的直系子节点 List > curNodeChildrenList = Lists.newArrayList(); //存放直系子节点以外的节点 List > otherNodeList = Lists.newArrayList(); Object pId = parentNode.get("id"); for (Map map : allList) { Object curPId = map.get("parentId"); if (ObjectUtils.isNotEmpty(curPId) && Objects.equals(pId,curPId)){ curNodeChildrenList.add(map); }else { otherNodeList.add(map); } } if (curNodeChildrenList.isEmpty()){ return curNodeChildrenList; } //每一层级都进行排序 curNodeChildrenList = sortJava7Map(curNodeChildrenList); //迭代直系子节点再获取子节点 for (Map map : curNodeChildrenList) { map.put("children",getJava7Children(map,otherNodeList)); } return curNodeChildrenList; }
给出一个结果集,构建树形结果集:
/** * 使用Java7的方式获取树形结构 * @param allList * @return */ public static List> getJava7ResultTree(List > allList){ //存放所有的一级节点 List > oneLevelNodeList = Lists.newArrayList(); for (Map map : allList) { if (ObjectUtils.isEmpty(map.get("parentId"))){ map.put("children",getJava7Children(map,allList)); oneLevelNodeList.add(map); } } return sortJava8Map(oneLevelNodeList); }
获取树形结构:
//转化为Map集合 List> mapList = BeanMapUtils.listBeanToListMap(nodePOs); //获取树形结构 List > java7ResultTree = getJava7ResultTree(mapList); //打印输出 System.out.println(JSON.toJSONString(java7ResultTree));
打印结果:
[{“orderNo”:”_0001″,”children”:[{“orderNo”:”_0002″,”children”:[],”name”:”二级节点1.1″,”id”:”2″,”parentId”:”1″},{“orderNo”:”_0003″,”children”:[],”name”:”二级节点1.2″,”id”:”3″,”parentId”:”1″}],”name”:”一级节点1″,”id”:”1″},{“orderNo”:”_0004″,”children”:[{“orderNo”:”_0005″,”children”:[],”name”:”二级节点2.1″,”id”:”5″,”parentId”:”4″},{“orderNo”:”_0006″,”children”:[{“orderNo”:”_0007″,”children”:[],”name”:”三级节点2.2.1″,”id”:”7″,”parentId”:”6″}],”name”:”二级节点2.2″,”id”:”6″,”parentId”:”4″}],”name”:”一级节点2″,”id”:”4″},{“orderNo”:”_0008″,”children”:[{“orderNo”:”_0009″,”children”:[{“orderNo”:”_0010″,”children”:[{“orderNo”:”_0011″,”children”:[{“orderNo”:”_0012″,”children”:[],”name”:”五级节点3.1.1.1.1″,”id”:”12″,”parentId”:”11″}],”name”:”四级节点3.1.1.1″,”id”:”11″,”parentId”:”10″}],”name”:”三级节点3.1.1″,”id”:”10″,”parentId”:”9″}],”name”:”二级节点3.1″,”id”:”9″,”parentId”:”8″}],”name”:”一级节点3″,”id”:”8″}]
树形结构搞定!
3.2、Java8及以上借助lamda表达式实现
Java7的方式虽然实现了树形结构,但是有一定的缺点,比如:代码量比较大,逻辑相对较复杂,那Java8是如何简化,如下所示:
既然Java8有lamda表达式,那代码我们能省就省,先看排序,一行代码搞定:
/** * 根据orderNo排序树形结构的每一个层级 * @param list * @return */ public static List> sortJava8Map(List > list){ if(CollectionUtils.isEmpty(list)){ return Lists.newArrayList(); } //关键之处,一行代码搞定 list.sort(Comparator.comparing(m -> String.valueOf(m.get("orderNo")))); return list; }
给定一个节点,获取它的所有子节点:
释义:
filter: 过滤,相当于for循环,再if条件判断。
peek: 给定一个节点,往它的children塞子节点。
/** * 根据父级节点获取所有的子集节点 * @param parentNode * @param allList * @return */ public static List> getJava8Children(Map parentNode, List > allList){ return allList.stream() .filter(curNode -> ObjectUtils.isNotEmpty(curNode.get("parentId")) && Objects.equals(curNode.get("parentId"),parentNode.get("id"))) .peek(m -> m.put("children", getJava8Children(m,allList))).collect(Collectors.toList()); }
给出一个结果集,构建树形结果集:
/** * 获取树形结构 * @param mapList * @return treeList 树形结果集 */ public static List> getJava8ResultTree(List > mapList){ if (CollectionUtils.isEmpty(mapList)){ return Lists.newArrayList(); } //filter过滤出所有的一级节点 return mapList.stream().filter(m -> Objects.equals(m.get("parentId"), null) || Objects.equals(m.get("parentId"), "")) .peek(m -> m.put("children", sortJava8Map(getJava8Children(m, mapList)))).collect(Collectors.toList()); }
获取树形结构:
//转化为Map集合 List> mapList = BeanMapUtils.listBeanToListMap(nodePOs); //获取树形结构 List > java8ResultTree = getJava8ResultTree(mapList); //打印输出 System.out.println(JSON.toJSONString(java8ResultTree));
打印结果:
[{“orderNo”:”_0001″,”children”:[{“orderNo”:”_0002″,”children”:[],”name”:”二级节点1.1″,”id”:”2″,”parentId”:”1″},{“orderNo”:”_0003″,”children”:[],”name”:”二级节点1.2″,”id”:”3″,”parentId”:”1″}],”name”:”一级节点1″,”id”:”1″},{“orderNo”:”_0004″,”children”:[{“orderNo”:”_0005″,”children”:[],”name”:”二级节点2.1″,”id”:”5″,”parentId”:”4″},{“orderNo”:”_0006″,”children”:[{“orderNo”:”_0007″,”children”:[],”name”:”三级节点2.2.1″,”id”:”7″,”parentId”:”6″}],”name”:”二级节点2.2″,”id”:”6″,”parentId”:”4″}],”name”:”一级节点2″,”id”:”4″},{“orderNo”:”_0008″,”children”:[{“orderNo”:”_0009″,”children”:[{“orderNo”:”_0010″,”children”:[{“orderNo”:”_0011″,”children”:[{“orderNo”:”_0012″,”children”:[],”name”:”五级节点3.1.1.1.1″,”id”:”12″,”parentId”:”11″}],”name”:”四级节点3.1.1.1″,”id”:”11″,”parentId”:”10″}],”name”:”三级节点3.1.1″,”id”:”10″,”parentId”:”9″}],”name”:”二级节点3.1″,”id”:”9″,”parentId”:”8″}],”name”:”一级节点3″,”id”:”8″}]
树形结构搞定!两种实现方式对比一下,你就说Java8的方式哇塞不哇塞!!!
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