前言
本篇可当做例题练习,
1.查询比”林红”年纪大的男学生信息
语句:
1 2 3 4 5 | select * from Student where Sex= '男' and year (Birth)-( select year (Birth) from Student --这里是需要告诉查询的表名,相当于嵌套 where Sname= '林红' ) |
2.检索所有学生的选课信息,包括学号、姓名、课程名、成绩,性别.
语句:
1 2 3 4 | select sc.sno,sname, course.Cno,Cname,Grade,Sex --这里如果两个表中都有同一个属性,则需要标明在哪个表,如sc.sno from student,sc,Course where student.Sno=sc.Sno and Sc.Cno=course.Cno |
3.查询已经选课的学生的学号、姓名、课程名、成绩.
语句:
1 2 3 | select sc.sno ,sname , Cname , Grade from student s , course c, sc where s.sno=sc.sno and c.cno=sc.cno |
(4)查询选修了“C语言程序设计”的学生的学号与姓名
–a.用内连接查询
语句:
1 2 3 | select sc.Sno,sname from student inner join sc on student.Sno=sc.Sno inner join course on sc.Cno =course.cno and Cname= 'C语言程序设计' |
–b.用连接查询
语句:
1 2 3 | select sc.Sno,sname from student,sc,course where student .Sno=sc.Sno and sc.Cno =course.cno and Cname= 'C语言程序设计' |
–c.用子查询
语句:
1 2 3 | select Sno,sname from student where Sno in ( select Sno from sc where Cno= ( select cno from course where Cname = 'C语言程序设计' )) |
(5)查询与”张虹”在同一个班级的学生学号、姓名、家庭住址
–a.用连接查询
语句:
1 2 | select a.Sno,a.sname,a.Home_addr from student a,student b where a.Classno =b.Classno and b.Sname = '张虹' and a.Sname!= '张虹' |
–b.用子查询
语句:
1 2 3 | select Sno,sname,Home_addr from student where classno=( select classno from student where sname= '张虹' ) and sname!= '张虹' |
(6)查询其他班级中比”051”班所有学生年龄大的学生的学号、姓名
代码1:
1 2 | select Sno,sname,Home_addr from student where classno!= '051' and Birth |
代码2:
1 2 | select Sno,sname,Home_addr from student where classno!= '051' and Birth |
(7)(选作)查询选修了全部课程的学生姓名。本题使用除运算的方法。
–由题意可得另一种语言,没有一个选了课的学生没有选course表里的课程。那么,我们需要两个NOT EXISTS表示双重否定;
语句:
1 2 3 4 5 6 7 | select Sname from student where not exists ( select * from course where not exists ( select * from sc where sno=student. sno and cno=Course.cno)) |
(8)查询至少选修了学生“20110002”选修的全部课程的学生的学号,姓名。
语句:
1 2 3 4 5 6 7 8 9 | select Sno, Sname from student where sno in ( select distinct sno from sc as sc1 where not exists ( select * from sc as sc2 where sc2.sno= '20110002' and not exists ( select * from sc as sc3 where sc3.Sno=sc1.sno and sc3.cno=sC2.cno) ) ) |
(9)检索选修了“高数”课且成绩至少高于选修课程号为“002″课程的学生的学号、课程号、成绩,并按成绩从高到低排列。
语句:
1 2 3 4 5 | select sc.Sno, sc.cno , grade from sc where grade > all ( select grade from sc where cno= '002' ) and Cno= ( select Cno from course where Cname= '高数' ) order by Grade desc |
(10)检索选修了至少3门以上课程的学生的学号、总成绩(不统计不及格的成绩),并要求按总成绩降序排列。
语句:
1 2 3 | select sno, SUM (grade) from sc where sno in ( select Sno from sc group by sno having COUNT (*)>=3) and Grade>=60 group by sno order by SUM (grade) desc |
(12)检索多于3名学生选修的并以3结尾的课程号的平均成绩。
语句:
1 2 3 4 | select avg (Grade) as 平均成绩 from sc where Cno like '%3' group by cno having count (Cno)>3 |
(13)检索最高分与最低分之差大于5分的学生的学号、姓名、最高分、最底分。
1 2 3 4 5 | select distinct sc.sno 学号,sname 姓名, max (grade) as 最高分, min (grade) as 最低分 from student,sc where sc.sno=student.Sno group by sc.sno , Sname having max (grade) - min (grade) >5 |
(14)创建一个表Student_other,结构同student,输入若干记录,部分记录和student表中的相同。
–创建过程:
1 2 3 4 5 6 7 8 9 10 11 | create table student__other ( Sno char (8) primary key , Sname varchar (8) not null , sex char (2) not null , Birth smalldatetime not null , Classno char (3) not null , Entrance_date smalldatetime not null , Home_addr varchar (40) , sdept char (2) not null , Postcode char (6) ) |
随意插入几条student表中没有的数据:
–a.查询同时出现在Student表和student_other表中的记录
语句:
1 2 | select * from student__other so ,student s where so.sno=s.sno |
—-b.查询Student表和Student_other表中的全部记录
代码:
1 2 3 | select * from student union select * from student__other |
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